Base | Representation |
---|---|
bin | 1011111011111111111011… |
… | …1111000000101110101101 |
3 | 1201110202221220102000010101 |
4 | 2332333332333000232231 |
5 | 3210021311133121310 |
6 | 43525421002311101 |
7 | 2523164502602320 |
oct | 276777677005655 |
9 | 51422856360111 |
10 | 13125403020205 |
11 | 42004a790a973 |
12 | 157b95aab8491 |
13 | 74294935c558 |
14 | 3353b6b7c7b7 |
15 | 17b64db5243a |
hex | beffefc0bad |
13125403020205 has 64 divisors (see below), whose sum is σ = 18905229527040. Its totient is φ = 8557486527744.
The previous prime is 13125403020017. The next prime is 13125403020227. The reversal of 13125403020205 is 50202030452131.
It is not a de Polignac number, because 13125403020205 - 213 = 13125403012013 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 224863354 + ... + 224921716.
It is an arithmetic number, because the mean of its divisors is an integer number (295394211360).
Almost surely, 213125403020205 is an apocalyptic number.
It is an amenable number.
13125403020205 is a deficient number, since it is larger than the sum of its proper divisors (5779826506835).
13125403020205 is a wasteful number, since it uses less digits than its factorization.
13125403020205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61778.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 13125403020205 its reverse (50202030452131), we get a palindrome (63327433472336).
The spelling of 13125403020205 in words is "thirteen trillion, one hundred twenty-five billion, four hundred three million, twenty thousand, two hundred five".
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