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13125410327 is a prime number
BaseRepresentation
bin11000011100101010…
…11101111000010111
31020212201202221002102
430032111131320113
5203340101112302
610010231032315
7643155101261
oct141625357027
936781687072
1013125410327
115625a52057
12266380b69b
1313123713b3
148c7292b31
1551c475702
hex30e55de17

13125410327 has 2 divisors, whose sum is σ = 13125410328. Its totient is φ = 13125410326.

The previous prime is 13125410317. The next prime is 13125410329. The reversal of 13125410327 is 72301452131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13125410327 - 28 = 13125410071 is a prime.

Together with 13125410329, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13125410327.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13125410329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562705163 + 6562705164.

It is an arithmetic number, because the mean of its divisors is an integer number (6562705164).

Almost surely, 213125410327 is an apocalyptic number.

13125410327 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125410327 is an equidigital number, since it uses as much as digits as its factorization.

13125410327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 13125410327 its reverse (72301452131), we get a palindrome (85426862458).

The spelling of 13125410327 in words is "thirteen billion, one hundred twenty-five million, four hundred ten thousand, three hundred twenty-seven".