Base | Representation |
---|---|
bin | 10011000110011001100… |
… | …010111101110001100011 |
3 | 11122110220020122121102211 |
4 | 103012121202331301203 |
5 | 133001041010332001 |
6 | 2442550103022551 |
7 | 163553664212425 |
oct | 23063142756143 |
9 | 4573806577384 |
10 | 1312541105251 |
11 | 466711266192 |
12 | 19246743aa57 |
13 | 96a063a698c |
14 | 47754dbc815 |
15 | 2421ee2d351 |
hex | 131998bdc63 |
1312541105251 has 4 divisors (see below), whose sum is σ = 1316816483752. Its totient is φ = 1308265726752.
The previous prime is 1312541105231. The next prime is 1312541105261. The reversal of 1312541105251 is 1525011452131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312541105251 - 27 = 1312541105123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312541105231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2137688790 + ... + 2137689403.
It is an arithmetic number, because the mean of its divisors is an integer number (329204120938).
Almost surely, 21312541105251 is an apocalyptic number.
1312541105251 is a deficient number, since it is larger than the sum of its proper divisors (4275378501).
1312541105251 is an equidigital number, since it uses as much as digits as its factorization.
1312541105251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4275378500.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 1312541105251 its reverse (1525011452131), we get a palindrome (2837552557382).
The spelling of 1312541105251 in words is "one trillion, three hundred twelve billion, five hundred forty-one million, one hundred five thousand, two hundred fifty-one".
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