Base | Representation |
---|---|
bin | 10011000110011001100… |
… | …010111101110001101101 |
3 | 11122110220020122121110012 |
4 | 103012121202331301231 |
5 | 133001041010332021 |
6 | 2442550103023005 |
7 | 163553664212441 |
oct | 23063142756155 |
9 | 4573806577405 |
10 | 1312541105261 |
11 | 4667112661a1 |
12 | 19246743aa65 |
13 | 96a063a6999 |
14 | 47754dbc821 |
15 | 2421ee2d35b |
hex | 131998bdc6d |
1312541105261 has 2 divisors, whose sum is σ = 1312541105262. Its totient is φ = 1312541105260.
The previous prime is 1312541105231. The next prime is 1312541105279. The reversal of 1312541105261 is 1625011452131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1309731469225 + 2809636036 = 1144435^2 + 53006^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312541105261 - 234 = 1295361236077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312541105231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656270552630 + 656270552631.
It is an arithmetic number, because the mean of its divisors is an integer number (656270552631).
Almost surely, 21312541105261 is an apocalyptic number.
It is an amenable number.
1312541105261 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312541105261 is an equidigital number, since it uses as much as digits as its factorization.
1312541105261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 1312541105261 its reverse (1625011452131), we get a palindrome (2937552557392).
The spelling of 1312541105261 in words is "one trillion, three hundred twelve billion, five hundred forty-one million, one hundred five thousand, two hundred sixty-one".
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