Base | Representation |
---|---|
bin | 10011000110011001100… |
… | …010111101110001001111 |
3 | 11122110220020122121102002 |
4 | 103012121202331301033 |
5 | 133001041010331411 |
6 | 2442550103022515 |
7 | 163553664212366 |
oct | 23063142756117 |
9 | 4573806577362 |
10 | 1312541105231 |
11 | 466711266174 |
12 | 19246743aa3b |
13 | 96a063a6975 |
14 | 47754dbc7dd |
15 | 2421ee2d33b |
hex | 131998bdc4f |
1312541105231 has 2 divisors, whose sum is σ = 1312541105232. Its totient is φ = 1312541105230.
The previous prime is 1312541105209. The next prime is 1312541105261. The reversal of 1312541105231 is 1325011452131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312541105231 - 210 = 1312541104207 is a prime.
It is a super-2 number, since 2×13125411052312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312541105194 and 1312541105203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312541105261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656270552615 + 656270552616.
It is an arithmetic number, because the mean of its divisors is an integer number (656270552616).
Almost surely, 21312541105231 is an apocalyptic number.
1312541105231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312541105231 is an equidigital number, since it uses as much as digits as its factorization.
1312541105231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 1312541105231 its reverse (1325011452131), we get a palindrome (2637552557362).
The spelling of 1312541105231 in words is "one trillion, three hundred twelve billion, five hundred forty-one million, one hundred five thousand, two hundred thirty-one".
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