13125411211045 has 8 divisors (see below), whose sum is σ = 18000563946624. Its totient is φ = 9000281973264.

The previous prime is 13125411211043. The next prime is 13125411211061. The reversal of 13125411211045 is 54011211452131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13125411211045 - 2¹ = 13125411211043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13125411210998 and 13125411211016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125411211043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 187505874409 + ... + 187505874478.

It is an arithmetic number, because the mean of its divisors is an integer number (2250070493328).

Almost surely, 2^{13125411211045} is an apocalyptic number.

It is an amenable number.

13125411211045 is a deficient number, since it is larger than the sum of its proper divisors (4875152735579).

13125411211045 is an equidigital number, since it uses as much as digits as its factorization.

13125411211045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 375011748899.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 13125411211045 its reverse (54011211452131), we get a palindrome (67136622663176).

The spelling of 13125411211045 in words is "thirteen trillion, one hundred twenty-five billion, four hundred eleven million, two hundred eleven thousand, forty-five".