Base | Representation |
---|---|
bin | 1011111011111111111101… |
… | …1110110000101100101110 |
3 | 1201110202222111001212001121 |
4 | 2332333333132300230232 |
5 | 3210021320300440100 |
6 | 43525421500531154 |
7 | 2523164633415421 |
oct | 276777736605456 |
9 | 51422874055047 |
10 | 13125411343150 |
11 | 4200501585037 |
12 | 157b961850aba |
13 | 74294acb4982 |
14 | 3353b7d079b8 |
15 | 17b64e74851a |
hex | befff7b0b2e |
13125411343150 has 12 divisors (see below), whose sum is σ = 24413265098352. Its totient is φ = 5250164537240.
The previous prime is 13125411343123. The next prime is 13125411343169. The reversal of 13125411343150 is 5134311452131.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 131254113382 + ... + 131254113481.
It is an arithmetic number, because the mean of its divisors is an integer number (2034438758196).
Almost surely, 213125411343150 is an apocalyptic number.
13125411343150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13125411343150 is a deficient number, since it is larger than the sum of its proper divisors (11287853755202).
13125411343150 is a wasteful number, since it uses less digits than its factorization.
13125411343150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 262508226875 (or 262508226870 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 13125411343150 its reverse (5134311452131), we get a palindrome (18259722795281).
The spelling of 13125411343150 in words is "thirteen trillion, one hundred twenty-five billion, four hundred eleven million, three hundred forty-three thousand, one hundred fifty".
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