Base | Representation |
---|---|
bin | 1011111011111111111110… |
… | …0110101111001100100001 |
3 | 1201110202222122000002100212 |
4 | 2332333333212233030201 |
5 | 3210021321314343040 |
6 | 43525422013423505 |
7 | 2523164660244545 |
oct | 276777746571441 |
9 | 51422878002325 |
10 | 13125413434145 |
11 | 4200502783031 |
12 | 157b96249ab95 |
13 | 74294b56764c |
14 | 3353b82cda25 |
15 | 17b64ea0cd65 |
hex | befff9af321 |
13125413434145 has 8 divisors (see below), whose sum is σ = 16676995892904. Its totient is φ = 9882664232704.
The previous prime is 13125413434127. The next prime is 13125413434151. The reversal of 13125413434145 is 54143431452131.
It can be written as a sum of positive squares in 4 ways, for example, as 7435967248609 + 5689446185536 = 2726897^2 + 2385256^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13125413434145 - 212 = 13125413430049 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 77208314234 + ... + 77208314403.
It is an arithmetic number, because the mean of its divisors is an integer number (2084624486613).
Almost surely, 213125413434145 is an apocalyptic number.
It is an amenable number.
13125413434145 is a deficient number, since it is larger than the sum of its proper divisors (3551582458759).
13125413434145 is a wasteful number, since it uses less digits than its factorization.
13125413434145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154416628659.
The product of its digits is 345600, while the sum is 41.
Adding to 13125413434145 its reverse (54143431452131), we get a palindrome (67268844886276).
The spelling of 13125413434145 in words is "thirteen trillion, one hundred twenty-five billion, four hundred thirteen million, four hundred thirty-four thousand, one hundred forty-five".
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