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13125421031 is a prime number
BaseRepresentation
bin11000011100101011…
…00000011111100111
31020212201210110202212
430032111200133213
5203340101433111
610010231154035
7643155144422
oct141625403747
936781713685
1013125421031
115625a5a0a8
12266381591b
131312376228
148c72969b9
1551c47898b
hex30e5607e7

13125421031 has 2 divisors, whose sum is σ = 13125421032. Its totient is φ = 13125421030.

The previous prime is 13125420991. The next prime is 13125421037. The reversal of 13125421031 is 13012452131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13125421031 - 214 = 13125404647 is a prime.

It is a super-2 number, since 2×131254210312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13125420988 and 13125421006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13125421037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562710515 + 6562710516.

It is an arithmetic number, because the mean of its divisors is an integer number (6562710516).

Almost surely, 213125421031 is an apocalyptic number.

13125421031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125421031 is an equidigital number, since it uses as much as digits as its factorization.

13125421031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 13125421031 its reverse (13012452131), we get a palindrome (26137873162).

The spelling of 13125421031 in words is "thirteen billion, one hundred twenty-five million, four hundred twenty-one thousand, thirty-one".