Base | Representation |
---|---|
bin | 11000011100101011… |
… | …00000011111100111 |
3 | 1020212201210110202212 |
4 | 30032111200133213 |
5 | 203340101433111 |
6 | 10010231154035 |
7 | 643155144422 |
oct | 141625403747 |
9 | 36781713685 |
10 | 13125421031 |
11 | 5625a5a0a8 |
12 | 266381591b |
13 | 1312376228 |
14 | 8c72969b9 |
15 | 51c47898b |
hex | 30e5607e7 |
13125421031 has 2 divisors, whose sum is σ = 13125421032. Its totient is φ = 13125421030.
The previous prime is 13125420991. The next prime is 13125421037. The reversal of 13125421031 is 13012452131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13125421031 - 214 = 13125404647 is a prime.
It is a super-2 number, since 2×131254210312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13125420988 and 13125421006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13125421037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562710515 + 6562710516.
It is an arithmetic number, because the mean of its divisors is an integer number (6562710516).
Almost surely, 213125421031 is an apocalyptic number.
13125421031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125421031 is an equidigital number, since it uses as much as digits as its factorization.
13125421031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 13125421031 its reverse (13012452131), we get a palindrome (26137873162).
The spelling of 13125421031 in words is "thirteen billion, one hundred twenty-five million, four hundred twenty-one thousand, thirty-one".
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