Base | Representation |
---|---|
bin | 11000011100101011… |
… | …00011100001111111 |
3 | 1020212201211002211121 |
4 | 30032111203201333 |
5 | 203340102332341 |
6 | 10010231331411 |
7 | 643155225613 |
oct | 141625434177 |
9 | 36781732747 |
10 | 13125433471 |
11 | 5625a68487 |
12 | 2663820b67 |
13 | 131237baa7 |
14 | 8c729b343 |
15 | 51c47c4d1 |
hex | 30e56387f |
13125433471 has 2 divisors, whose sum is σ = 13125433472. Its totient is φ = 13125433470.
The previous prime is 13125433463. The next prime is 13125433547. The reversal of 13125433471 is 17433452131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13125433471 - 23 = 13125433463 is a prime.
It is a super-3 number, since 3×131254334713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13125433421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562716735 + 6562716736.
It is an arithmetic number, because the mean of its divisors is an integer number (6562716736).
Almost surely, 213125433471 is an apocalyptic number.
13125433471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125433471 is an equidigital number, since it uses as much as digits as its factorization.
13125433471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 30240, while the sum is 34.
The spelling of 13125433471 in words is "thirteen billion, one hundred twenty-five million, four hundred thirty-three thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •