13125433547 has 2 divisors, whose sum is σ = 13125433548. Its totient is φ = 13125433546.

The previous prime is 13125433471. The next prime is 13125433549. The reversal of 13125433547 is 74533452131.

13125433547 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13125433547 - 2¹⁸ = 13125171403 is a prime.

Together with 13125433549, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13125433547.

It is not a weakly prime, because it can be changed into another prime (13125433549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562716773 + 6562716774.

It is an arithmetic number, because the mean of its divisors is an integer number (6562716774).

Almost surely, 2^13125433547 is an apocalyptic number.

13125433547 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125433547 is an equidigital number, since it uses as much as digits as its factorization.

13125433547 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 151200, while the sum is 38.

Adding to 13125433547 its reverse (74533452131), we get a palindrome (87658885678).

The spelling of 13125433547 in words is "thirteen billion, one hundred twenty-five million, four hundred thirty-three thousand, five hundred forty-seven".