Base | Representation |
---|---|
bin | 1011111100000010010100… |
… | …0111000011010111001111 |
3 | 1201110211121111000012012020 |
4 | 2333000211013003113033 |
5 | 3210024113410143401 |
6 | 43530004252141223 |
7 | 2523216400506243 |
oct | 277004507032717 |
9 | 51424544005166 |
10 | 13126042662351 |
11 | 42007a5984543 |
12 | 157bab9167813 |
13 | 742a1ba27b28 |
14 | 335437ac4423 |
15 | 17b689da0d36 |
hex | bf0251c35cf |
13126042662351 has 4 divisors (see below), whose sum is σ = 17501390216472. Its totient is φ = 8750695108232.
The previous prime is 13126042662347. The next prime is 13126042662361. The reversal of 13126042662351 is 15326624062131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13126042662351 - 22 = 13126042662347 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13126042662361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187673777056 + ... + 2187673777061.
It is an arithmetic number, because the mean of its divisors is an integer number (4375347554118).
Almost surely, 213126042662351 is an apocalyptic number.
13126042662351 is a deficient number, since it is larger than the sum of its proper divisors (4375347554121).
13126042662351 is an equidigital number, since it uses as much as digits as its factorization.
13126042662351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4375347554120.
The product of its (nonzero) digits is 311040, while the sum is 42.
The spelling of 13126042662351 in words is "thirteen trillion, one hundred twenty-six billion, forty-two million, six hundred sixty-two thousand, three hundred fifty-one".
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