Base | Representation |
---|---|
bin | 1011111100000011010111… |
… | …1110101101100110101110 |
3 | 1201110212100012120102102110 |
4 | 2333000311332231212232 |
5 | 3210030203334020000 |
6 | 43530052322304450 |
7 | 2523226405263141 |
oct | 277006576554656 |
9 | 51425305512373 |
10 | 13126325688750 |
11 | 420093071545a |
12 | 157bb77ab8126 |
13 | 742a65561b81 |
14 | 33546351a058 |
15 | 17b6a4b5a850 |
hex | bf035fad9ae |
13126325688750 has 40 divisors (see below), whose sum is σ = 32805313170696. Its totient is φ = 3500353516000.
The previous prime is 13126325688733. The next prime is 13126325688803. The reversal of 13126325688750 is 5788652362131.
It is a Smith number, since the sum of its digits (57) coincides with the sum of the digits of its prime factors.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 1750173009 + ... + 1750180508.
Almost surely, 213126325688750 is an apocalyptic number.
13126325688750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13126325688750 is an abundant number, since it is smaller than the sum of its proper divisors (19678987481946).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13126325688750 is an equidigital number, since it uses as much as digits as its factorization.
13126325688750 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3500353542 (or 3500353527 counting only the distinct ones).
The product of its (nonzero) digits is 14515200, while the sum is 57.
The spelling of 13126325688750 in words is "thirteen trillion, one hundred twenty-six billion, three hundred twenty-five million, six hundred eighty-eight thousand, seven hundred fifty".
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