Base | Representation |
---|---|
bin | 1011111100000011101010… |
… | …0000011010110101011111 |
3 | 1201110212112111110211012211 |
4 | 2333000322200122311133 |
5 | 3210030332304234011 |
6 | 43530104034141251 |
7 | 2523231316636606 |
oct | 277007240326537 |
9 | 51425474424184 |
10 | 13126401633631 |
11 | 420096a576a20 |
12 | 157bb99421827 |
13 | 742a78202580 |
14 | 33546d648a3d |
15 | 17b6ab65cb21 |
hex | bf03a81ad5f |
13126401633631 has 16 divisors (see below), whose sum is σ = 15651394674048. Its totient is φ = 10850756796000.
The previous prime is 13126401633623. The next prime is 13126401633731. The reversal of 13126401633631 is 13633610462131.
It is not a de Polignac number, because 13126401633631 - 23 = 13126401633623 is a prime.
It is a super-2 number, since 2×131264016336312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13126401633731) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 685012945 + ... + 685032106.
It is an arithmetic number, because the mean of its divisors is an integer number (978212167128).
Almost surely, 213126401633631 is an apocalyptic number.
13126401633631 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13126401633631 is a deficient number, since it is larger than the sum of its proper divisors (2524993040417).
13126401633631 is a wasteful number, since it uses less digits than its factorization.
13126401633631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1370045142.
The product of its (nonzero) digits is 139968, while the sum is 40.
The spelling of 13126401633631 in words is "thirteen trillion, one hundred twenty-six billion, four hundred one million, six hundred thirty-three thousand, six hundred thirty-one".
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