Base | Representation |
---|---|
bin | 1011111100001101101101… |
… | …0110000001110111100100 |
3 | 1201111010111120000011012102 |
4 | 2333003123112001313210 |
5 | 3210101344102313300 |
6 | 43531231510311232 |
7 | 2523355224012536 |
oct | 277033326016744 |
9 | 51433446004172 |
10 | 13129100041700 |
11 | 4202024775935 |
12 | 1580611058518 |
13 | 7430b827c536 |
14 | 335647b85856 |
15 | 17b7b84cb0d5 |
hex | bf0db581de4 |
13129100041700 has 36 divisors (see below), whose sum is σ = 28490338488612. Its totient is φ = 5251604736000.
The previous prime is 13129100041693. The next prime is 13129100041703. The reversal of 13129100041700 is 714000192131.
It can be written as a sum of positive squares in 6 ways, for example, as 972148672576 + 12156951369124 = 985976^2 + 3486682^2 .
It is not an unprimeable number, because it can be changed into a prime (13129100041703) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18615500 + ... + 19307900.
Almost surely, 213129100041700 is an apocalyptic number.
13129100041700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13129100041700 is an abundant number, since it is smaller than the sum of its proper divisors (15361238446912).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13129100041700 is a wasteful number, since it uses less digits than its factorization.
13129100041700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 882032 (or 882025 counting only the distinct ones).
The product of its (nonzero) digits is 1512, while the sum is 29.
The spelling of 13129100041700 in words is "thirteen trillion, one hundred twenty-nine billion, one hundred million, forty-one thousand, seven hundred".
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