Base | Representation |
---|---|
bin | 11000011101001101… |
… | …11110011010111001 |
3 | 1020220001102010000102 |
4 | 30032212332122321 |
5 | 203342240000212 |
6 | 10010513245145 |
7 | 643242105356 |
oct | 141646763271 |
9 | 36801363012 |
10 | 13130000057 |
11 | 56285a7419 |
12 | 26652637b5 |
13 | 13132ba505 |
14 | 8c7b2962d |
15 | 51ca805c2 |
hex | 30e9be6b9 |
13130000057 has 2 divisors, whose sum is σ = 13130000058. Its totient is φ = 13130000056.
The previous prime is 13130000053. The next prime is 13130000111. The reversal of 13130000057 is 75000003131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12013036816 + 1116963241 = 109604^2 + 33421^2 .
It is a cyclic number.
It is not a de Polignac number, because 13130000057 - 22 = 13130000053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13129999993 and 13130000038.
It is not a weakly prime, because it can be changed into another prime (13130000053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565000028 + 6565000029.
It is an arithmetic number, because the mean of its divisors is an integer number (6565000029).
Almost surely, 213130000057 is an apocalyptic number.
It is an amenable number.
13130000057 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130000057 is an equidigital number, since it uses as much as digits as its factorization.
13130000057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 315, while the sum is 20.
Adding to 13130000057 its reverse (75000003131), we get a palindrome (88130003188).
The spelling of 13130000057 in words is "thirteen billion, one hundred thirty million, fifty-seven", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •