131300120011111 has 4 divisors (see below), whose sum is σ = 131348409870400. Its totient is φ = 131251830151824.

The previous prime is 131300120011087. The next prime is 131300120011139. The reversal of 131300120011111 is 111110021003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131300120011111 - 2⁵ = 131300120011079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131300120015111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24144925566 + ... + 24144931003.

It is an arithmetic number, because the mean of its divisors is an integer number (32837102467600).

Almost surely, 2^{131300120011111} is an apocalyptic number.

131300120011111 is a deficient number, since it is larger than the sum of its proper divisors (48289859289).

131300120011111 is an equidigital number, since it uses as much as digits as its factorization.

131300120011111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48289859288.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 131300120011111 its reverse (111110021003131), we get a palindrome (242410141014242).

The spelling of 131300120011111 in words is "one hundred thirty-one trillion, three hundred billion, one hundred twenty million, eleven thousand, one hundred eleven".