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131300200651 = 153138574427
BaseRepresentation
bin111101001001000011…
…0100001000011001011
3110112220112111021121111
41322102012201003023
54122400322410101
6140152442551151
712325512201544
oct1722206410313
9415815437544
10131300200651
11507585a4124
12215442084b7
13c4c637cc29
1464d803d4cb
153637093251
hex1e921a10cb

131300200651 has 4 divisors (see below), whose sum is σ = 131308790392. Its totient is φ = 131291610912.

The previous prime is 131300200649. The next prime is 131300200693. The reversal of 131300200651 is 156002003131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 156002003131 = 1312000154087.

It is a cyclic number.

It is not a de Polignac number, because 131300200651 - 21 = 131300200649 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131300200631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4271901 + ... + 4302526.

It is an arithmetic number, because the mean of its divisors is an integer number (32827197598).

Almost surely, 2131300200651 is an apocalyptic number.

131300200651 is a deficient number, since it is larger than the sum of its proper divisors (8589741).

131300200651 is an equidigital number, since it uses as much as digits as its factorization.

131300200651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8589740.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 131300200651 its reverse (156002003131), we get a palindrome (287302203782).

The spelling of 131300200651 in words is "one hundred thirty-one billion, three hundred million, two hundred thousand, six hundred fifty-one".

Divisors: 1 15313 8574427 131300200651