Base | Representation |
---|---|
bin | 10011000110110101011… |
… | …111101110111101111111 |
3 | 11122112002220222221212000 |
4 | 103012311133232331333 |
5 | 133003021031121343 |
6 | 2443104413313343 |
7 | 163601420011446 |
oct | 23066537567577 |
9 | 4575086887760 |
10 | 1313010020223 |
11 | 466931a20a20 |
12 | 192578495853 |
13 | 96a7c596c65 |
14 | 4779b3a1d5d |
15 | 2424b1a5ed3 |
hex | 131b57eef7f |
1313010020223 has 32 divisors (see below), whose sum is σ = 2167186129920. Its totient is φ = 778832498880.
The previous prime is 1313010020221. The next prime is 1313010020243. The reversal of 1313010020223 is 3220200103131.
It is not a de Polignac number, because 1313010020223 - 21 = 1313010020221 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313010020196 and 1313010020205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313010020221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47016990 + ... + 47044907.
It is an arithmetic number, because the mean of its divisors is an integer number (67724566560).
Almost surely, 21313010020223 is an apocalyptic number.
1313010020223 is a deficient number, since it is larger than the sum of its proper divisors (854176109697).
1313010020223 is a wasteful number, since it uses less digits than its factorization.
1313010020223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94061964 (or 94061958 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 1313010020223 its reverse (3220200103131), we get a palindrome (4533210123354).
The spelling of 1313010020223 in words is "one trillion, three hundred thirteen billion, ten million, twenty thousand, two hundred twenty-three".
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