Base | Representation |
---|---|
bin | 11101110110101011101100… |
… | …110100001001100000001110 |
3 | 122012220021011001002220221221 |
4 | 131312223230310021200032 |
5 | 114202214200033111420 |
6 | 1143130523042313554 |
7 | 36441123144433654 |
oct | 3566535464114016 |
9 | 565807131086857 |
10 | 131301123332110 |
11 | 38922548120466 |
12 | 128870546588ba |
13 | 583584830c284 |
14 | 245d0189dadd4 |
15 | 102a69be12caa |
hex | 776aecd0980e |
131301123332110 has 8 divisors (see below), whose sum is σ = 236342021997816. Its totient is φ = 52520449332840.
The previous prime is 131301123332003. The next prime is 131301123332161. The reversal of 131301123332110 is 11233321103131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1313011233321102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6565056166596 + ... + 6565056166615.
It is an arithmetic number, because the mean of its divisors is an integer number (29542752749727).
Almost surely, 2131301123332110 is an apocalyptic number.
131301123332110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131301123332110 is a deficient number, since it is larger than the sum of its proper divisors (105040898665706).
131301123332110 is a wasteful number, since it uses less digits than its factorization.
131301123332110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13130112333218.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 131301123332110 its reverse (11233321103131), we get a palindrome (142534444435241).
The spelling of 131301123332110 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred twenty-three million, three hundred thirty-two thousand, one hundred ten".
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