Search a number
-
+
131301132000 = 2535317643633
BaseRepresentation
bin111101001001000101…
…0000100011011100000
3110112220121020121011220
41322102022010123200
54122401042211000
6140152514535040
712325523131053
oct1722212043340
9415817217156
10131301132000
115075907a935
1221544597480
13c4c6617b1c
1464d8202a9a
1536371c91a0
hex1e922846e0

131301132000 has 192 divisors, whose sum is σ = 455445716544. Its totient is φ = 32953958400.

The previous prime is 131301131959. The next prime is 131301132077. The reversal of 131301132000 is 231103131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 117817 + ... + 525816.

It is an arithmetic number, because the mean of its divisors is an integer number (2372113107).

Almost surely, 2131301132000 is an apocalyptic number.

131301132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131301132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (227722858272).

131301132000 is an abundant number, since it is smaller than the sum of its proper divisors (324144584544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131301132000 is a wasteful number, since it uses less digits than its factorization.

131301132000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 643678 (or 643660 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 131301132000 its reverse (231103131), we get a palindrome (131532235131).

The spelling of 131301132000 in words is "one hundred thirty-one billion, three hundred one million, one hundred thirty-two thousand".