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131301132303 = 3113978822191
BaseRepresentation
bin111101001001000101…
…0000100100000001111
3110112220121020121121010
41322102022010200033
54122401042213203
6140152514540303
712325523131665
oct1722212044017
9415817217533
10131301132303
1150759080090
1221544597693
13c4c6617cc3
1464d8202c35
1536371c9303
hex1e9228480f

131301132303 has 8 divisors (see below), whose sum is σ = 190983465216. Its totient is φ = 79576443800.

The previous prime is 131301132301. The next prime is 131301132317. The reversal of 131301132303 is 303231103131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131301132303 - 21 = 131301132301 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131301132303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131301132301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1989411063 + ... + 1989411128.

It is an arithmetic number, because the mean of its divisors is an integer number (23872933152).

Almost surely, 2131301132303 is an apocalyptic number.

131301132303 is a deficient number, since it is larger than the sum of its proper divisors (59682332913).

131301132303 is a wasteful number, since it uses less digits than its factorization.

131301132303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3978822205.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 131301132303 its reverse (303231103131), we get a palindrome (434532235434).

The spelling of 131301132303 in words is "one hundred thirty-one billion, three hundred one million, one hundred thirty-two thousand, three hundred three".

Divisors: 1 3 11 33 3978822191 11936466573 43767044101 131301132303