131301133000119 has 48 divisors (see below), whose sum is σ = 194666224401792. Its totient is φ = 85234880695104.

The previous prime is 131301133000073. The next prime is 131301133000151. The reversal of 131301133000119 is 911000331103131.

131301133000119 is a `hidden beast` number, since 1 + 3 + 130 + 113 + 300 + 0 + 119 = 666.

It is not a de Polignac number, because 131301133000119 - 2⁸ = 131301132999863 is a prime.

It is a super-3 number, since 3×131301133000119³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 131301133000092 and 131301133000101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131301133002119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 685718197 + ... + 685909649.

It is an arithmetic number, because the mean of its divisors is an integer number (4055546341704).

Almost surely, 2^{131301133000119} is an apocalyptic number.

131301133000119 is a deficient number, since it is larger than the sum of its proper divisors (63365091401673).

131301133000119 is a wasteful number, since it uses less digits than its factorization.

131301133000119 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 196956 (or 196953 counting only the distinct ones).

The product of its (nonzero) digits is 729, while the sum is 27.

The spelling of 131301133000119 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred thirty-three million, one hundred nineteen", and thus it is an aban number.