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131301133000120 = 2353282528325003
BaseRepresentation
bin11101110110101011101101…
…011001000001110110111000
3122012220021011201022002222101
4131312223231121001312320
5114202214210022000440
61143130524025433144
736441123322551406
oct3566535531016670
9565807151262871
10131301133000120
1138922552624156
121288705793b7b4
13583584a3159a5
14245d019dd6476
15102a69cbc269a
hex776aed641db8

131301133000120 has 16 divisors (see below), whose sum is σ = 295427549250360. Its totient is φ = 52520453200032.

The previous prime is 131301133000073. The next prime is 131301133000151. The reversal of 131301133000120 is 21000331103131.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1641264162462 + ... + 1641264162541.

Almost surely, 2131301133000120 is an apocalyptic number.

131301133000120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131301133000120 is an abundant number, since it is smaller than the sum of its proper divisors (164126416250240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131301133000120 is a wasteful number, since it uses less digits than its factorization.

131301133000120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3282528325014 (or 3282528325010 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131301133000120 its reverse (21000331103131), we get a palindrome (152301464103251).

The spelling of 131301133000120 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred thirty-three million, one hundred twenty", and thus it is an aban number.

Divisors: 1 2 4 5 8 10 20 40 3282528325003 6565056650006 13130113300012 16412641625015 26260226600024 32825283250030 65650566500060 131301133000120