Base | Representation |
---|---|
bin | 11101110110101011101101… |
… | …011001000001111000011001 |
3 | 122012220021011201022010002222 |
4 | 131312223231121001320121 |
5 | 114202214210022001332 |
6 | 1143130524025433425 |
7 | 36441123322551605 |
oct | 3566535531017031 |
9 | 565807151263088 |
10 | 131301133000217 |
11 | 38922552624234 |
12 | 1288705793b875 |
13 | 583584a315a4b |
14 | 245d019dd6505 |
15 | 102a69cbc2712 |
hex | 776aed641e19 |
131301133000217 has 2 divisors, whose sum is σ = 131301133000218. Its totient is φ = 131301133000216.
The previous prime is 131301133000151. The next prime is 131301133000231. The reversal of 131301133000217 is 712000331103131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 107715773861641 + 23585359138576 = 10378621^2 + 4856476^2 .
It is a cyclic number.
It is not a de Polignac number, because 131301133000217 - 218 = 131301132738073 is a prime.
It is not a weakly prime, because it can be changed into another prime (131301133006217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650566500108 + 65650566500109.
It is an arithmetic number, because the mean of its divisors is an integer number (65650566500109).
Almost surely, 2131301133000217 is an apocalyptic number.
It is an amenable number.
131301133000217 is a deficient number, since it is larger than the sum of its proper divisors (1).
131301133000217 is an equidigital number, since it uses as much as digits as its factorization.
131301133000217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 26.
Adding to 131301133000217 its reverse (712000331103131), we get a palindrome (843301464103348).
The spelling of 131301133000217 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred thirty-three million, two hundred seventeen", and thus it is an aban number.
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