1313011440220 has 12 divisors (see below), whose sum is σ = 2757324024504. Its totient is φ = 525204576080.

The previous prime is 1313011440203. The next prime is 1313011440277. The reversal of 1313011440220 is 220441103131.

It is a junction number, because it is equal to n+sod(n) for n = 1313011440191 and 1313011440200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32825285986 + ... + 32825286025.

It is an arithmetic number, because the mean of its divisors is an integer number (229777002042).

Almost surely, 2^{1313011440220} is an apocalyptic number.

1313011440220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1313011440220 is an abundant number, since it is smaller than the sum of its proper divisors (1444312584284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313011440220 is a wasteful number, since it uses less digits than its factorization.

1313011440220 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65650572020 (or 65650572018 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1313011440220 its reverse (220441103131), we get a palindrome (1533452543351).

The spelling of 1313011440220 in words is "one trillion, three hundred thirteen billion, eleven million, four hundred forty thousand, two hundred twenty".