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13130141111 = 27253481787
BaseRepresentation
bin11000011101001111…
…00000110110110111
31020220001200021111122
430032213200312313
5203342304003421
610010520254155
7643243233533
oct141647406667
936801607448
1013130141111
11562869339a
12266531135b
131313339789
148c7b64bc3
1551caac2ab
hex30e9e0db7

13130141111 has 4 divisors (see below), whose sum is σ = 13130650152. Its totient is φ = 13129632072.

The previous prime is 13130141081. The next prime is 13130141137. The reversal of 13130141111 is 11114103131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13130141111 - 214 = 13130124727 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13130141111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13130141611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213641 + ... + 268146.

It is an arithmetic number, because the mean of its divisors is an integer number (3282662538).

Almost surely, 213130141111 is an apocalyptic number.

13130141111 is a deficient number, since it is larger than the sum of its proper divisors (509041).

13130141111 is an equidigital number, since it uses as much as digits as its factorization.

13130141111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 509040.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 13130141111 its reverse (11114103131), we get a palindrome (24244244242).

The spelling of 13130141111 in words is "thirteen billion, one hundred thirty million, one hundred forty-one thousand, one hundred eleven".

Divisors: 1 27253 481787 13130141111