Base | Representation |
---|---|
bin | 1011111100010001100110… |
… | …0110000110111110001110 |
3 | 1201111020012100020022020021 |
4 | 2333010121212012332032 |
5 | 3210111013434204202 |
6 | 43531523255412354 |
7 | 2523423135206224 |
oct | 277043146067616 |
9 | 51436170208207 |
10 | 13130144444302 |
11 | 4202510266a86 |
12 | 15808629840ba |
13 | 743223765142 |
14 | 335706770b14 |
15 | 17b82a02da37 |
hex | bf119986f8e |
13130144444302 has 4 divisors (see below), whose sum is σ = 19695216666456. Its totient is φ = 6565072222150.
The previous prime is 13130144444299. The next prime is 13130144444357. The reversal of 13130144444302 is 20344444103131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282536111074 + ... + 3282536111077.
It is an arithmetic number, because the mean of its divisors is an integer number (4923804166614).
Almost surely, 213130144444302 is an apocalyptic number.
13130144444302 is a deficient number, since it is larger than the sum of its proper divisors (6565072222154).
13130144444302 is an equidigital number, since it uses as much as digits as its factorization.
13130144444302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6565072222153.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 13130144444302 its reverse (20344444103131), we get a palindrome (33474588547433).
The spelling of 13130144444302 in words is "thirteen trillion, one hundred thirty billion, one hundred forty-four million, four hundred forty-four thousand, three hundred two".
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