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13130144444303 = 28374628179219
BaseRepresentation
bin1011111100010001100110…
…0110000110111110001111
31201111020012100020022020022
42333010121212012332033
53210111013434204203
643531523255412355
72523423135206225
oct277043146067617
951436170208208
1013130144444303
114202510266a87
1215808629840bb
13743223765143
14335706770b15
1517b82a02da38
hexbf119986f8f

13130144444303 has 4 divisors (see below), whose sum is σ = 13134772626360. Its totient is φ = 13125516262248.

The previous prime is 13130144444299. The next prime is 13130144444357. The reversal of 13130144444303 is 30344444103131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13130144444303 - 22 = 13130144444299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13130144494303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2314086773 + ... + 2314092446.

It is an arithmetic number, because the mean of its divisors is an integer number (3283693156590).

Almost surely, 213130144444303 is an apocalyptic number.

13130144444303 is a deficient number, since it is larger than the sum of its proper divisors (4628182057).

13130144444303 is an equidigital number, since it uses as much as digits as its factorization.

13130144444303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4628182056.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 13130144444303 its reverse (30344444103131), we get a palindrome (43474588547434).

The spelling of 13130144444303 in words is "thirteen trillion, one hundred thirty billion, one hundred forty-four million, four hundred forty-four thousand, three hundred three".

Divisors: 1 2837 4628179219 13130144444303