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1313020200302 = 2656510100151
BaseRepresentation
bin10011000110110110000…
…110100100010101101110
311122112010122011011021222
4103012312012210111232
5133003031132402202
62443105415423342
7163601602361126
oct23066606442556
94575118134258
101313020200302
11466937744408
1219257b984b52
1396a8171c785
144779c891c86
152424c0174a2
hex131b61a456e

1313020200302 has 4 divisors (see below), whose sum is σ = 1969530300456. Its totient is φ = 656510100150.

The previous prime is 1313020200287. The next prime is 1313020200311. The reversal of 1313020200302 is 2030020203131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×13130202003022 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328255050074 + ... + 328255050077.

It is an arithmetic number, because the mean of its divisors is an integer number (492382575114).

Almost surely, 21313020200302 is an apocalyptic number.

1313020200302 is a deficient number, since it is larger than the sum of its proper divisors (656510100154).

1313020200302 is an equidigital number, since it uses as much as digits as its factorization.

1313020200302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 656510100153.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 1313020200302 its reverse (2030020203131), we get a palindrome (3343040403433).

The spelling of 1313020200302 in words is "one trillion, three hundred thirteen billion, twenty million, two hundred thousand, three hundred two".

Divisors: 1 2 656510100151 1313020200302