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1313021501141 = 7187574500163
BaseRepresentation
bin10011000110110110001…
…011100001111011010101
311122112010201121020201012
4103012312023201323111
5133003032001014031
62443105503342005
7163601616416510
oct23066613417325
94575121536635
101313021501141
11466938452789
121925802b1905
1396a81a868bc
144779cb0dd77
152424c1c2b2b
hex131b62e1ed5

1313021501141 has 4 divisors (see below), whose sum is σ = 1500596001312. Its totient is φ = 1125447000972.

The previous prime is 1313021501093. The next prime is 1313021501173. The reversal of 1313021501141 is 1411051203131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-1313021501141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313021551141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93787250075 + ... + 93787250088.

It is an arithmetic number, because the mean of its divisors is an integer number (375149000328).

Almost surely, 21313021501141 is an apocalyptic number.

It is an amenable number.

1313021501141 is a deficient number, since it is larger than the sum of its proper divisors (187574500171).

1313021501141 is an equidigital number, since it uses as much as digits as its factorization.

1313021501141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187574500170.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 1313021501141 its reverse (1411051203131), we get a palindrome (2724072704272).

The spelling of 1313021501141 in words is "one trillion, three hundred thirteen billion, twenty-one million, five hundred one thousand, one hundred forty-one".

Divisors: 1 7 187574500163 1313021501141