Base | Representation |
---|---|
bin | 11101110110101100101101… |
… | …101001110001111010101111 |
3 | 122012220100221211222221101121 |
4 | 131312230231221301322233 |
5 | 114202223412022224403 |
6 | 1143131223021521411 |
7 | 36441162123541303 |
oct | 3566545551617257 |
9 | 565810854887347 |
10 | 131302211133103 |
11 | 38922a5616344a |
12 | 128872b8a13267 |
13 | 583598c7ab4ba |
14 | 245d0bd281d03 |
15 | 102a7126893bd |
hex | 776b2da71eaf |
131302211133103 has 2 divisors, whose sum is σ = 131302211133104. Its totient is φ = 131302211133102.
The previous prime is 131302211133101. The next prime is 131302211133109. The reversal of 131302211133103 is 301331112203131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131302211133103 - 21 = 131302211133101 is a prime.
Together with 131302211133101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131302211133101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651105566551 + 65651105566552.
It is an arithmetic number, because the mean of its divisors is an integer number (65651105566552).
Almost surely, 2131302211133103 is an apocalyptic number.
131302211133103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131302211133103 is an equidigital number, since it uses as much as digits as its factorization.
131302211133103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 131302211133103 its reverse (301331112203131), we get a palindrome (432633323336234).
The spelling of 131302211133103 in words is "one hundred thirty-one trillion, three hundred two billion, two hundred eleven million, one hundred thirty-three thousand, one hundred three".
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