Base | Representation |
---|---|
bin | 1011111100010001111110… |
… | …0010101100100100100001 |
3 | 1201111020110021222002012011 |
4 | 2333010133202230210201 |
5 | 3210111220004304100 |
6 | 43531541222032521 |
7 | 2523425456216152 |
oct | 277043742544441 |
9 | 51436407862164 |
10 | 13130244213025 |
11 | 420256160a775 |
12 | 1580890278741 |
13 | 74323b3275a4 |
14 | 335715b01929 |
15 | 17b833b89bba |
hex | bf11f8ac921 |
13130244213025 has 24 divisors (see below), whose sum is σ = 16999087167360. Its totient is φ = 10041758855040.
The previous prime is 13130244213019. The next prime is 13130244213049. The reversal of 13130244213025 is 52031244203131.
13130244213025 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13130244213025 - 25 = 13130244212993 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5505205 + ... + 7521154.
It is an arithmetic number, because the mean of its divisors is an integer number (708295298640).
Almost surely, 213130244213025 is an apocalyptic number.
It is an amenable number.
13130244213025 is a deficient number, since it is larger than the sum of its proper divisors (3868842954335).
13130244213025 is a wasteful number, since it uses less digits than its factorization.
13130244213025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13028145 (or 13028140 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13130244213025 its reverse (52031244203131), we get a palindrome (65161488416156).
The spelling of 13130244213025 in words is "thirteen trillion, one hundred thirty billion, two hundred forty-four million, two hundred thirteen thousand, twenty-five".
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