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1313031114000 = 24335346435237
BaseRepresentation
bin10011000110110110110…
…000001100110100010000
311122112011101200122002000
4103012312300030310100
5133003041431122000
62443110445354000
7163602064214364
oct23066660146420
94575141618060
101313031114000
11466942918aa1
12192583568900
1396a83a71198
14477a00d32a4
152424ce71000
hex131b6c0cd10

1313031114000 has 320 divisors, whose sum is σ = 4705480615680. Its totient is φ = 349999372800.

The previous prime is 1313031113957. The next prime is 1313031114047. The reversal of 1313031114000 is 4111303131.

1313031114000 is a `hidden beast` number, since 1 + 313 + 0 + 311 + 1 + 40 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 250719382 + ... + 250724618.

It is an arithmetic number, because the mean of its divisors is an integer number (14704626924).

Almost surely, 21313031114000 is an apocalyptic number.

1313031114000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1313031114000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2352740307840).

1313031114000 is an abundant number, since it is smaller than the sum of its proper divisors (3392449501680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313031114000 is a wasteful number, since it uses less digits than its factorization.

1313031114000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9912 (or 9890 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1313031114000 its reverse (4111303131), we get a palindrome (1317142417131).

The spelling of 1313031114000 in words is "one trillion, three hundred thirteen billion, thirty-one million, one hundred fourteen thousand".