131304062220001 has 4 divisors (see below), whose sum is σ = 143240795149104. Its totient is φ = 119367329290900.

The previous prime is 131304062219929. The next prime is 131304062220167. The reversal of 131304062220001 is 100022260403131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131304062220001 - 2⁹ = 131304062219489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131304062220301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5968366464535 + ... + 5968366464556.

It is an arithmetic number, because the mean of its divisors is an integer number (35810198787276).

Almost surely, 2^{131304062220001} is an apocalyptic number.

131304062220001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131304062220001 is a deficient number, since it is larger than the sum of its proper divisors (11936732929103).

131304062220001 is a wasteful number, since it uses less digits than its factorization.

131304062220001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11936732929102.

The product of its (nonzero) digits is 1728, while the sum is 25.

The spelling of 131304062220001 in words is "one hundred thirty-one trillion, three hundred four billion, sixty-two million, two hundred twenty thousand, one".