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1313100302321 is a prime number
BaseRepresentation
bin10011000110111010111…
…000001000011111110001
311122112100012212202121102
4103012322320020133301
5133003212134133241
62443121400334145
7163603564260533
oct23067270103761
94575305782542
101313100302321
11466978985225
121925a2774355
1396a951b7412
14477a9383853
152425408b39b
hex131bae087f1

1313100302321 has 2 divisors, whose sum is σ = 1313100302322. Its totient is φ = 1313100302320.

The previous prime is 1313100302303. The next prime is 1313100302323. The reversal of 1313100302321 is 1232030013131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 829921000000 + 483179302321 = 911000^2 + 695111^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313100302321 - 218 = 1313100040177 is a prime.

Together with 1313100302323, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313100302293 and 1313100302302.

It is not a weakly prime, because it can be changed into another prime (1313100302323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656550151160 + 656550151161.

It is an arithmetic number, because the mean of its divisors is an integer number (656550151161).

Almost surely, 21313100302321 is an apocalyptic number.

It is an amenable number.

1313100302321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313100302321 is an equidigital number, since it uses as much as digits as its factorization.

1313100302321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 1313100302321 its reverse (1232030013131), we get a palindrome (2545130315452).

The spelling of 1313100302321 in words is "one trillion, three hundred thirteen billion, one hundred million, three hundred two thousand, three hundred twenty-one".