Base | Representation |
---|---|
bin | 11000011101010101… |
… | …10101010011100111 |
3 | 1020220010022111011222 |
4 | 30032222311103213 |
5 | 203343014330203 |
6 | 10010551050555 |
7 | 643253516534 |
oct | 141652652347 |
9 | 36803274158 |
10 | 13131011303 |
11 | 5629128163 |
12 | 2665670a5b |
13 | 1313582897 |
14 | 8c7d0dd8b |
15 | 51cbd0038 |
hex | 30eab54e7 |
13131011303 has 2 divisors, whose sum is σ = 13131011304. Its totient is φ = 13131011302.
The previous prime is 13131011269. The next prime is 13131011339. The reversal of 13131011303 is 30311013131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13131011303 - 212 = 13131007207 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131011393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565505651 + 6565505652.
It is an arithmetic number, because the mean of its divisors is an integer number (6565505652).
Almost surely, 213131011303 is an apocalyptic number.
13131011303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131011303 is an equidigital number, since it uses as much as digits as its factorization.
13131011303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 13131011303 its reverse (30311013131), we get a palindrome (43442024434).
The spelling of 13131011303 in words is "thirteen billion, one hundred thirty-one million, eleven thousand, three hundred three".
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