Base | Representation |
---|---|
bin | 111101001001010110… |
… | …0010110110010111010 |
3 | 110112221020011020120022 |
4 | 1322102230112302322 |
5 | 4122410342320442 |
6 | 140153435330442 |
7 | 12325662414356 |
oct | 1722254266272 |
9 | 415836136508 |
10 | 131310120122 |
11 | 50763159835 |
12 | 215475b0a22 |
13 | c4c8443c3c |
14 | 64d94a2466 |
15 | 3637da23d2 |
hex | 1e92b16cba |
131310120122 has 4 divisors (see below), whose sum is σ = 196965180186. Its totient is φ = 65655060060.
The previous prime is 131310120103. The next prime is 131310120131. The reversal of 131310120122 is 221021013131.
131310120122 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 131202603961 + 107516161 = 362219^2 + 10369^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 131310120122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32827530029 + ... + 32827530032.
Almost surely, 2131310120122 is an apocalyptic number.
131310120122 is a deficient number, since it is larger than the sum of its proper divisors (65655060064).
131310120122 is an equidigital number, since it uses as much as digits as its factorization.
131310120122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65655060063.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 131310120122 its reverse (221021013131), we get a palindrome (352331133253).
The spelling of 131310120122 in words is "one hundred thirty-one billion, three hundred ten million, one hundred twenty thousand, one hundred twenty-two".
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