Search a number
-
+
131310120122 = 265655060061
BaseRepresentation
bin111101001001010110…
…0010110110010111010
3110112221020011020120022
41322102230112302322
54122410342320442
6140153435330442
712325662414356
oct1722254266272
9415836136508
10131310120122
1150763159835
12215475b0a22
13c4c8443c3c
1464d94a2466
153637da23d2
hex1e92b16cba

131310120122 has 4 divisors (see below), whose sum is σ = 196965180186. Its totient is φ = 65655060060.

The previous prime is 131310120103. The next prime is 131310120131. The reversal of 131310120122 is 221021013131.

131310120122 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 131202603961 + 107516161 = 362219^2 + 10369^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 131310120122.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32827530029 + ... + 32827530032.

Almost surely, 2131310120122 is an apocalyptic number.

131310120122 is a deficient number, since it is larger than the sum of its proper divisors (65655060064).

131310120122 is an equidigital number, since it uses as much as digits as its factorization.

131310120122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65655060063.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 131310120122 its reverse (221021013131), we get a palindrome (352331133253).

The spelling of 131310120122 in words is "one hundred thirty-one billion, three hundred ten million, one hundred twenty thousand, one hundred twenty-two".

Divisors: 1 2 65655060061 131310120122