Base | Representation |
---|---|
bin | 1011111100010100110111… |
… | …1101111101000100010111 |
3 | 1201111022110120121011112221 |
4 | 2333011031331331010113 |
5 | 3210114313404013143 |
6 | 43532150404323211 |
7 | 2523453664562101 |
oct | 277051575750427 |
9 | 51438416534487 |
10 | 13131023110423 |
11 | 4202921247929 |
12 | 1580a690a3507 |
13 | 7433337cc21a |
14 | 33578b336571 |
15 | 17b87c2442ed |
hex | bf14df7d117 |
13131023110423 has 2 divisors, whose sum is σ = 13131023110424. Its totient is φ = 13131023110422.
The previous prime is 13131023110369. The next prime is 13131023110433. The reversal of 13131023110423 is 32401132013131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13131023110423 - 217 = 13131022979351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131023110433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565511555211 + 6565511555212.
It is an arithmetic number, because the mean of its divisors is an integer number (6565511555212).
Almost surely, 213131023110423 is an apocalyptic number.
13131023110423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131023110423 is an equidigital number, since it uses as much as digits as its factorization.
13131023110423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13131023110423 its reverse (32401132013131), we get a palindrome (45532155123554).
The spelling of 13131023110423 in words is "thirteen trillion, one hundred thirty-one billion, twenty-three million, one hundred ten thousand, four hundred twenty-three".
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