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13131023110433 is a prime number
BaseRepresentation
bin1011111100010100110111…
…1101111101000100100001
31201111022110120121011120022
42333011031331331010201
53210114313404013213
643532150404323225
72523453664562114
oct277051575750441
951438416534508
1013131023110433
114202921247938
121580a690a3515
137433337cc227
1433578b33657b
1517b87c244308
hexbf14df7d121

13131023110433 has 2 divisors, whose sum is σ = 13131023110434. Its totient is φ = 13131023110432.

The previous prime is 13131023110423. The next prime is 13131023110451. The reversal of 13131023110433 is 33401132013131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8290811908129 + 4840211202304 = 2879377^2 + 2200048^2 .

It is a cyclic number.

It is not a de Polignac number, because 13131023110433 - 26 = 13131023110369 is a prime.

It is a super-2 number, since 2×131310231104332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13131023110423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565511555216 + 6565511555217.

It is an arithmetic number, because the mean of its divisors is an integer number (6565511555217).

Almost surely, 213131023110433 is an apocalyptic number.

It is an amenable number.

13131023110433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131023110433 is an equidigital number, since it uses as much as digits as its factorization.

13131023110433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 13131023110433 its reverse (33401132013131), we get a palindrome (46532155123564).

The spelling of 13131023110433 in words is "thirteen trillion, one hundred thirty-one billion, twenty-three million, one hundred ten thousand, four hundred thirty-three".