1313103414011 has 2 divisors, whose sum is σ = 1313103414012. Its totient is φ = 1313103414010.

The previous prime is 1313103413987. The next prime is 1313103414013. The reversal of 1313103414011 is 1104143013131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313103414011 is a prime.

It is a super-2 number, since 2×1313103414011² (a number of 25 digits) contains 22 as substring.

Together with 1313103414013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1313103414013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656551707005 + 656551707006.

It is an arithmetic number, because the mean of its divisors is an integer number (656551707006).

Almost surely, 2^{1313103414011} is an apocalyptic number.

1313103414011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313103414011 is an equidigital number, since it uses as much as digits as its factorization.

1313103414011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1313103414011 its reverse (1104143013131), we get a palindrome (2417246427142).

The spelling of 1313103414011 in words is "one trillion, three hundred thirteen billion, one hundred three million, four hundred fourteen thousand, eleven".