Base | Representation |
---|---|
bin | 1011111100010100111011… |
… | …1111101101101010000111 |
3 | 1201111022111210000222011121 |
4 | 2333011032333231222013 |
5 | 3210114332312130212 |
6 | 43532152222014411 |
7 | 2523454264236553 |
oct | 277051677555207 |
9 | 51438453028147 |
10 | 13131040348807 |
11 | 420292aa51327 |
12 | 1580a72a17407 |
13 | 743337256654 |
14 | 33578d742863 |
15 | 17b87d9ebd07 |
hex | bf14efeda87 |
13131040348807 has 2 divisors, whose sum is σ = 13131040348808. Its totient is φ = 13131040348806.
The previous prime is 13131040348753. The next prime is 13131040348813. The reversal of 13131040348807 is 70884304013131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13131040348807 - 215 = 13131040316039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131040346807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565520174403 + 6565520174404.
It is an arithmetic number, because the mean of its divisors is an integer number (6565520174404).
Almost surely, 213131040348807 is an apocalyptic number.
13131040348807 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131040348807 is an equidigital number, since it uses as much as digits as its factorization.
13131040348807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 193536, while the sum is 43.
The spelling of 13131040348807 in words is "thirteen trillion, one hundred thirty-one billion, forty million, three hundred forty-eight thousand, eight hundred seven".
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