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131310503 is a prime number
BaseRepresentation
bin1111101001110…
…10001110100111
3100011002021010222
413310322032213
5232103414003
621010234555
73153056312
oct764721647
9304067128
10131310503
1168137585
1237b85a5b
132128712c
1413621979
15b7dbc38
hex7d3a3a7

131310503 has 2 divisors, whose sum is σ = 131310504. Its totient is φ = 131310502.

The previous prime is 131310497. The next prime is 131310523. The reversal of 131310503 is 305013131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131310503 - 220 = 130261927 is a prime.

It is a super-2 number, since 2×1313105032 = 34484896396226018, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131310523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655251 + 65655252.

It is an arithmetic number, because the mean of its divisors is an integer number (65655252).

Almost surely, 2131310503 is an apocalyptic number.

131310503 is a deficient number, since it is larger than the sum of its proper divisors (1).

131310503 is an equidigital number, since it uses as much as digits as its factorization.

131310503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 131310503 is about 11459.0795005533. The cubic root of 131310503 is about 508.2762553369.

Adding to 131310503 its reverse (305013131), we get a palindrome (436323634).

The spelling of 131310503 in words is "one hundred thirty-one million, three hundred ten thousand, five hundred three".