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13131110311031 is a prime number
BaseRepresentation
bin1011111100010101001100…
…1010100110010001110111
31201111022200122200102022002
42333011103022212101313
53210120003214423111
643532203201325515
72523456104015216
oct277052312462167
951438618612262
1013131110311031
114202966496a49
121580a9233689b
137433488b0c0b
14335798b5507d
1517b884c1b63b
hexbf1532a6477

13131110311031 has 2 divisors, whose sum is σ = 13131110311032. Its totient is φ = 13131110311030.

The previous prime is 13131110310977. The next prime is 13131110311063. The reversal of 13131110311031 is 13011301113131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13131110311031 - 214 = 13131110294647 is a prime.

It is a super-2 number, since 2×131311103110312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13131110310994 and 13131110311012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131110311531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565555155515 + 6565555155516.

It is an arithmetic number, because the mean of its divisors is an integer number (6565555155516).

Almost surely, 213131110311031 is an apocalyptic number.

13131110311031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131110311031 is an equidigital number, since it uses as much as digits as its factorization.

13131110311031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 20.

Adding to 13131110311031 its reverse (13011301113131), we get a palindrome (26142411424162).

The spelling of 13131110311031 in words is "thirteen trillion, one hundred thirty-one billion, one hundred ten million, three hundred eleven thousand, thirty-one".