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1313111303 = 7268969761
BaseRepresentation
bin100111001000100…
…0111110100000111
310101111211222001222
41032101013310013
510142124030203
6334144310555
744353155560
oct11621076407
93344758058
101313111303
11614242a59
1230791245b
1317c078a4a
14c6575167
157a430038
hex4e447d07

1313111303 has 8 divisors (see below), whose sum is σ = 1501278240. Its totient is φ = 1125089280.

The previous prime is 1313111291. The next prime is 1313111323. The reversal of 1313111303 is 3031113131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1313111303 - 218 = 1312849159 is a prime.

It is a super-2 number, since 2×13131113032 = 3448522588132715618, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313111323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16058 + ... + 53703.

It is an arithmetic number, because the mean of its divisors is an integer number (187659780).

Almost surely, 21313111303 is an apocalyptic number.

1313111303 is a deficient number, since it is larger than the sum of its proper divisors (188166937).

1313111303 is an equidigital number, since it uses as much as digits as its factorization.

1313111303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72457.

The product of its (nonzero) digits is 81, while the sum is 17.

The square root of 1313111303 is about 36236.8776662670. The cubic root of 1313111303 is about 1095.0497403786.

Adding to 1313111303 its reverse (3031113131), we get a palindrome (4344224434).

The spelling of 1313111303 in words is "one billion, three hundred thirteen million, one hundred eleven thousand, three hundred three".

Divisors: 1 7 2689 18823 69761 488327 187587329 1313111303