Base | Representation |
---|---|
bin | 1011111100010101001110… |
… | …1111100100010011111111 |
3 | 1201111022201022220210020002 |
4 | 2333011103233210103333 |
5 | 3210120013210033203 |
6 | 43532204145144515 |
7 | 2523456252260522 |
oct | 277052357442377 |
9 | 51438638823202 |
10 | 13131120002303 |
11 | 4202970a06166 |
12 | 1580a9562b13b |
13 | 74334a8c50b4 |
14 | 33579a158bb9 |
15 | 17b8859d2d88 |
hex | bf153be44ff |
13131120002303 has 4 divisors (see below), whose sum is σ = 13132866866280. Its totient is φ = 13129373138328.
The previous prime is 13131120002291. The next prime is 13131120002359. The reversal of 13131120002303 is 30320002113131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13131120002303 - 28 = 13131120002047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13131120002393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 873420713 + ... + 873435746.
It is an arithmetic number, because the mean of its divisors is an integer number (3283216716570).
Almost surely, 213131120002303 is an apocalyptic number.
13131120002303 is a deficient number, since it is larger than the sum of its proper divisors (1746863977).
13131120002303 is an equidigital number, since it uses as much as digits as its factorization.
13131120002303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1746863976.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 13131120002303 its reverse (30320002113131), we get a palindrome (43451122115434).
The spelling of 13131120002303 in words is "thirteen trillion, one hundred thirty-one billion, one hundred twenty million, two thousand, three hundred three".
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