Base | Representation |
---|---|
bin | 11101110110110101000110… |
… | …110011110101010001010111 |
3 | 122012221020012220122222112121 |
4 | 131312311012303311101113 |
5 | 114202400341110231041 |
6 | 1143135313152200411 |
7 | 36441631343352256 |
oct | 3566650663652127 |
9 | 565836186588477 |
10 | 131311223133271 |
11 | 38926860200575 |
12 | 12888bb2b39107 |
13 | 58367978a088c |
14 | 245d6d60dc79d |
15 | 102aa8d9367d1 |
hex | 776d46cf5457 |
131311223133271 has 2 divisors, whose sum is σ = 131311223133272. Its totient is φ = 131311223133270.
The previous prime is 131311223133269. The next prime is 131311223133329. The reversal of 131311223133271 is 172331322113131.
It is a weak prime.
It is an emirp because it is prime and its reverse (172331322113131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131311223133271 - 21 = 131311223133269 is a prime.
Together with 131311223133269, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131311223134271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655611566635 + 65655611566636.
It is an arithmetic number, because the mean of its divisors is an integer number (65655611566636).
Almost surely, 2131311223133271 is an apocalyptic number.
131311223133271 is a deficient number, since it is larger than the sum of its proper divisors (1).
131311223133271 is an equidigital number, since it uses as much as digits as its factorization.
131311223133271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13608, while the sum is 34.
The spelling of 131311223133271 in words is "one hundred thirty-one trillion, three hundred eleven billion, two hundred twenty-three million, one hundred thirty-three thousand, two hundred seventy-one".
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