Base | Representation |
---|---|
bin | 10011000110111011101… |
… | …000101101000100100000 |
3 | 11122112101002211122121121 |
4 | 103012323220231010200 |
5 | 133003223414110130 |
6 | 2443122533302024 |
7 | 163604110431262 |
oct | 23067350550440 |
9 | 4575332748547 |
10 | 1313113035040 |
11 | 466985091534 |
12 | 1925a6a94914 |
13 | 96a97a24a81 |
14 | 477aad39b32 |
15 | 24255253d7a |
hex | 131bba2d120 |
1313113035040 has 48 divisors (see below), whose sum is σ = 3103782192000. Its totient is φ = 524982332160.
The previous prime is 1313113035007. The next prime is 1313113035071. The reversal of 1313113035040 is 405303113131.
It is a junction number, because it is equal to n+sod(n) for n = 1313113034996 and 1313113035014.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1732926 + ... + 2372605.
It is an arithmetic number, because the mean of its divisors is an integer number (64662129000).
Almost surely, 21313113035040 is an apocalyptic number.
1313113035040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1313113035040 is an abundant number, since it is smaller than the sum of its proper divisors (1790669156960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1313113035040 is a wasteful number, since it uses less digits than its factorization.
1313113035040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4107545 (or 4107537 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 1313113035040 its reverse (405303113131), we get a palindrome (1718416148171).
The spelling of 1313113035040 in words is "one trillion, three hundred thirteen billion, one hundred thirteen million, thirty-five thousand, forty".
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