Base | Representation |
---|---|
bin | 11101110110110101110101… |
… | …000111110101101111100111 |
3 | 122012221022020001201111201002 |
4 | 131312311311013311233213 |
5 | 114202403434013130043 |
6 | 1143135522230023515 |
7 | 36441656526621026 |
oct | 3566656507655747 |
9 | 565838201644632 |
10 | 131312000130023 |
11 | 3892711985a749 |
12 | 1288918b1a7b9b |
13 | 583688c85b37b |
14 | 245d76b39a8bd |
15 | 102aad6c67bb8 |
hex | 776d751f5be7 |
131312000130023 has 2 divisors, whose sum is σ = 131312000130024. Its totient is φ = 131312000130022.
The previous prime is 131312000129987. The next prime is 131312000130029. The reversal of 131312000130023 is 320031000213131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131312000130023 - 220 = 131311999081447 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131312000129977 and 131312000130004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131312000130029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656000065011 + 65656000065012.
It is an arithmetic number, because the mean of its divisors is an integer number (65656000065012).
Almost surely, 2131312000130023 is an apocalyptic number.
131312000130023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131312000130023 is an equidigital number, since it uses as much as digits as its factorization.
131312000130023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 131312000130023 its reverse (320031000213131), we get a palindrome (451343000343154).
The spelling of 131312000130023 in words is "one hundred thirty-one trillion, three hundred twelve billion, one hundred thirty thousand, twenty-three".
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