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13131213332231 is a prime number
BaseRepresentation
bin1011111100010101100101…
…0011100101111100000111
31201111022221211112102211002
42333011121103211330013
53210120211103112411
643532221321403515
72523461464462451
oct277053123457407
951438854472732
1013131213332231
114202a09661335
121580b0093959b
137433640418c7
143357a86d12d1
1517b88dcbb33b
hexbf1594e5f07

13131213332231 has 2 divisors, whose sum is σ = 13131213332232. Its totient is φ = 13131213332230.

The previous prime is 13131213332197. The next prime is 13131213332233. The reversal of 13131213332231 is 13223331213131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13131213332231 - 226 = 13131146223367 is a prime.

It is a super-2 number, since 2×131312133322312 (a number of 27 digits) contains 22 as substring.

Together with 13131213332233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13131213332194 and 13131213332203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131213332233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565606666115 + 6565606666116.

It is an arithmetic number, because the mean of its divisors is an integer number (6565606666116).

Almost surely, 213131213332231 is an apocalyptic number.

13131213332231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131213332231 is an equidigital number, since it uses as much as digits as its factorization.

13131213332231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5832, while the sum is 29.

Adding to 13131213332231 its reverse (13223331213131), we get a palindrome (26354544545362).

The spelling of 13131213332231 in words is "thirteen trillion, one hundred thirty-one billion, two hundred thirteen million, three hundred thirty-two thousand, two hundred thirty-one".